Question

$\large\red{\sf{Question}}$
$\large\purple{\sf{y \leqslant - 15x + 3000}} \\ \large\purple{\sf{y \leqslant 5x}}$
Refer to attachment for question​

Answer 1

Answer

The value of b comes out when take equality. So now we have to solve this equation ⇒ \sf -15x+3000=5x−15x+3000=5x to find the possible value for 'b'.

Let's solve your equation step-by-step.

\sf -15x+3000=5x−15x+3000=5x

Step 1: Subtract 5x from both sides.

\sf -15x+3000-5x=5x-5x−15x+3000−5x=5x−5x

\sf -20x+3000=0−20x+3000=0

Step 2: Subtract 3000 from both sides.

\sf -20x+3000-3000=0-3000−20x+3000−3000=0−3000

\sf -20x=-3000−20x=−3000

Step 3: Divide both sides by -20.

\sf \frac{-20x}{20} = \frac{-3000}{20}

20

−20x

=

20

−3000

\sf x =150x=150

So now to find the final answer we must multiply 5 from 150.

\sf 150\times 5 = 750150×5=750

∴The maximum possible value of 'b' is 750.

\rule{300}{0.5}

Answer 2

Step-by-step explanation:

The maximum value of b occurs when take equality.

⇒−15x+3000=5x

⇒−20x=−3000

⇒−20x=−3000

⇒x=150

Therefore , y=5×150=750

Hence maximum possible value of b=750