Math, asked by Oodleslt, 16 days ago


    \large{\star\tt{ \underline{ \overline{ \blue{QUESTION:}}}}}
ABC is a right-angled triangle and O is the midpoint of the side opposite to the right angle. Explain why O is equidistant from A, B and C.

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Answers

Answered by babitabaruah2017
3

Answer:

Opposite sides are parallel and equal to each other and all the interior angles are right angles. The property of rectangle states that the diagonals are of equal length and bisect each other. Hence, AO = OC = BO = OD. Thus, O is equidistant from A, B and C.

Step-by-step explanation:

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Answered by SɳσɯDɾσρ
36

Solution:-

Draw lines

AD and DC such that AD||BC, AB||DC

AD = BC, AB = DC

ABCD is a rectangle form property opposite sides are equal and parallel to each other and all

the interior angles are of 90°.

In a rectangle, again property diagonals are of equal length and also these bisect each other.

Hence, AO = OC = BO = OD

So, O is equidistant from A, B, and C.1 \:

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