Question

$\large\text{\underline{Question}}$ If $f(x)=\dfrac{3x-\sqrt{9x^{2}+4x+8}}{2}$ and $g(x)=\dfrac{3x+\sqrt{9x^{2}+4x+8}}{2}$, are $f(x)$ and $g(x)$ decreasing and increasing functions respectively? Why? How do you show that $\dfrac{3x-\sqrt{9x^{2}+4x+8}}{2}\ \textless \ -\dfrac{1}{3}\ \textless \ \dfrac{3x+\sqrt{9x^{2}+4x+8}}{2}$ for real values of $x$? $\large\text{\underline{Note}}$ I will mark brainliest to the correct answer. So please explain well.​

Answer 1

Answer:

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Step-by-step explanation:

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