Question

$\large \textbf { Maths \: Question}$

1) A hemispherical bowl of internal radius 9cm contains a liquid. This liquid is to be filled into cylindrical shaped small bottels of diameter 3cm and height 4cm. How many bottles are required to empty the bowl.

Answer 1

No. of bottles = Volume(bowl) ÷ volume(bottle)

$= \frac{ \frac{2}{3} \times \pi \times {r}^{3} }{\pi \times {R}^{2} \times h} \\ \\ = \frac{2}{3} \times \frac{ {r}^{3} }{ {R}^{2} \times h} \\ \\ = \frac{2}{3} \times \frac{9 \times 9 \times 9}{1.5 \times 1.5 \times 4} \\ \\ = \frac{2}{3} \times \frac{729}{9} \\ \\ = \frac{2}{3} \times 81 \\ \\ = 2 \times 27 \\ \\ = 54 \: \: bottles$

#CaptainAmerica

Answer 2

hey

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for hemisphere

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radius (r) = 9 cm

•volume of hemisphere =2/3πr^3

= 2/3×22/7×9×9×9

for cylinder

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radius( R)= diameter /2 = 3/2 cm

height = 4 cm

•volume of cylinder =πr^2h

= 22/7×3/2×3/2×4

req no of bottles = volume of hemisphere/ volume of 1 cylinder

now refer to the attachment

hope helped

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