Question

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The sum of two numbers is 64, and the second number is 16 less than the first. Find the numbers.
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Answer 1

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first number = 40

second number = 24

Step-by-step explanation:

Let the unknown number be x

first number = x

second number = x-16

Sum of these numbers = 64

x + x - 16 = 64

2x = 64 + 16

2x = 80

x = 80 ÷ 2

x = 40

first number = x = 40

second number = x-16 = 40-16 = 24

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Answer 2

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Let The First No. be x

And Second No. be x-16

Sum of the missing no.= 64

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Solving The Question.

$x + x - 16 = 64 \\ \\ \implies 2x = 64 + 16 \\ \\ \implies 2x = 80 \\ \\ \implies x = \cancel\frac{80}{2} \\ \\ \implies \: x = 40$

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First No.= x=40

$\therefore$ second no. is

= x - 16

= 40 - 16

= 24

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