Question

$\Large{\textsf{\underline{Please Answer the Question.}}}$

$<b><u>Note :</b></u>$

• Given in Attachment.​

Answer 1

Solution:

Let the number be 'x'.

Subtracting $\sf{\frac{1}{2}}$ from the number:

$\implies$ $\boxed{\sf{x - \frac{1}{2}}}$

Now,

According to the problem given,

Subtract 1/2 from a number and multiply the result by 1/2, you get 1/8.

So:

$\sf{(x - \frac{1}{2} ) \times \frac{1}{2} = \frac{1}{8}}$

$\implies$ $\sf{(x - \frac{1}{2} ) = \frac{1}{8} \times \frac{2}{1}}$

$\implies$ $\sf{x - \frac{1}{2} = \frac{1}{4}}$

$\implies$ $\sf{x = \frac{1}{4} + \frac{1}{2}}$

$\implies$ $\sf{x = \frac{(1 + 2)}{4}}$

$\implies$ $\sf{x = \frac{3}{4}}$

Therefore,

Required number (x) = $\sf{\frac{3}{4}}$

Answer 2

$\Large{\mathfrak{\underline{Answer:}}} \\ \\ \sf \frac{3}{4} \\ \\ \Large{\mathfrak{\underline{Step-by-step \: explanation:}}} \\ \\ \textsf{Let the number be x.} \\ \\ \textrm{ATQ,} \\ \\ \sf (x - \frac{1}{2}) × \frac{1}{2} = \frac{1}{8} \\ \sf ⇒ \frac{x}{2} - \frac{1}{4} = \frac{1}{8} \\ \sf ⇒ \frac{x}{2} = \frac{1}{8} + \frac{1}{4} \\ \sf ⇒ \frac{x}{2} = \frac{1}{8} + \frac{2}{8} \\ \sf ⇒ \frac{x}{2} = \frac{(1+2)}{8} \\ \sf ⇒ x = \frac{3}{8} × 2 \\ \sf ⇒ x = \frac{6}{8} \\ \sf ⇒ x = \frac{3}{4} \\ \\ \large \sf \underline{\boxed{\sf Thanks ..!!!}}$