Question

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◑A ship anchored in a port has a ladder which hangs over the side. The length of the ladder is 200cm, the distance between each rung in 20cm and the bottom rung touches the water. The tide rises at a rate of 10cm an hour. When will the water reach the fifth rung?



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Answer 1

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⛦Question:-

• A ship anchored in a port has a ladder which hangs over the side. The length of the ladder is 200cm, the distance between each rung in 20cm and the bottom rung touches the water. The tide rises at a rate of 10cm an hour. When will the water reach the fifth rung?

⛦Answer:-

Here,

• The total length of ladder is 200cm

• and number of rungs=10(each rung is 20cm long,

• so the no of rungs are 200/20 = 10

we have to find out when the water reaches at 100cm

we have to find out when the water reaches at 100cm(bcoz, 5th rung i=half ladder )

the tide increase by 10cm/h

ie,

↬ 10x=100

• Now the 20cm of ladder is under water (in question:last rung is in water,and distance between each rung is 20cm).

↬so now length of ladder is 80 cm

ie,

⟼10x = 80

⟼x=80/10

⟼x=8

ie, tide takes 8 hours to reach at fifth level

And we αre done! :D

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Answer 2

Answer:

FIFTH RUNG = 20 * 5 = 100 CM

AMT RISEN IN EACH HR = 10 CM

  SO THE NO OF HOURS IT TAKES FOR THE WATER TO RISE TO THE FIFTH RUNG= 100/10 =  10 HRS