Question

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Two chords AB, CD of lengths 5 cm, 11 cm respectively of α circle αre pαrαllel. If the distαnce between AB & CD is 3 cm, find the rαdius of the circle.
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Answer 1

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Answer is attached :)

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Answer 2

Answer:

Solution:

MB = 2.5 cm and ND = 5.5 cm [The perpendicular drawn from the center of the circle to the chords bisects it.]

Let OM = x and ON = 6 - x

Consider ΔOMB

By Pythagoras theorem,

OM2 + MB2 = OB2

x2 + 2.52 = OB2

x2 + 6.25 = OB2...(1)

Consider ΔOND

By Pythagoras theorem,

ON2 + ND2 = OD2

(6 - x)² + 5.52 = OD2

36 + x2 - 12x + 30.25 = OD2

x2 - 12x + 66.25 = OD2 ... (2)

OB and OD are the radii of the circle. Therefore OB = OD.

Thus, OB2 = OD2

Equating (1) and (2) we get,

x2 + 6.25 = x2 - 12x + 66.25

12x = 60

x = 5

Substituting the value of x in (1),

OB2 = x2 + 6.25

OB2 = 52 + 6.25

OB2 = 31.25

OB = 5.59 (approx.)

Thus, we get the radius of the circle = 5.59 cm.