Question

$]\Large{\underbrace{\sf{\orange{Question:}}}}$[ Refer to the attached picture! :) ]______________$\large{\underline{\bf{Source}}}$ - Class 9th, R.D. Sharma Mathematics Book...[/tex]


please give it correct ...i will mark brainlist..​

Answer 1

$\Large{\underbrace{\underline{\bf{QUESTION\:}}}}:$

Find the value of 'p'.

$\dagger\:\bf\red{5^{(p\:-\:5)}\times{2^{(p\:-\:5)}}\:=\:5\:}$

$\Large{\underbrace{\underline{\bf{ANSWER\:}}}}:$

${\bf{Given\::}}$

$\red\checkmark\:\tt{5^{(p\:-\:5)}\times{2^{(p\:-\:5)}}\:=\:5\:}$

$\\ {\bf{To\: Find\::}}$

The value of 'p'.

$\\ {\bf{Properties\::}}$

$\dagger\:\bf\blue{a^{1}\:=\:a\:}$

$\dagger\:\bf\purple{a^{0}\:=\:1\:}$

$\\ {\bf{Solution\::}}$

$:\implies\:\tt{5^{(p\:-\:5)}\times{2^{(p\:-\:5)}}\:=\:5\:}$

☛ We also write as,

$:\implies\:\tt{5^{(p\:-\:5)}\times{2^{(p\:-\:5)}}\:=\:5\times{1}\:}$

$:\implies\:\tt{5^{(p\:-\:5)}\times{2^{(p\:-\:5)}}\:=\:5^{1}\times{2^{0}}\:}$

☛ Compare both sides, we get

$:\implies\:\tt{5^{(p\:-\:5)}\:=\:5^{1}\:~~~\&\:~~~\:{2^{(p\:-\:5)}}\:=\:2^{0}\:}$

$:\implies\:\tt{p\:-\:5\:=\:1\:~~~Or\:~~~\:p\:-\:5\:=\:0\:}$

$:\implies\:\tt{p\:=\:1\:+\:5\:~~~Or\:~~~\:p\:=\:0\:+\:5\:}$

$:\implies\:{\tt{\green {p\:=\:6}}}\:~~~Or\:~~~\:{\tt{\green {p\:=\:5}}}\:$

Answer 2

Answer:

Hi Mate

Step-by-step explanation:

Your answer is in the attachment ☝☝

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