Question

$\large\underline\bold{QUESTION}$


✯.A body is thrown vertically up to reach its maximum height in t seconds. The total time from the time of projection to reach a point at half of its maximum height while returning( in seconds ) is


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Answer 1

Answer:

At max

m

height v=o,

v=u−gt,⇒t=

g

u

=

g

2H

−(1)

Now situation is,

We want time to reach C.

Time from AtoB=t

Time from BtoC⇒v

c

2

=v

B

2

+2g

2

H

2

H

=+

2

1

gt

1

2

v

C

=

gH

t

1

=

g

H

⇒t

1

=

2

t

(from(1))

So, total time =t+t

1

=t+

2

t

=t(1+

2

1

)

Answer 2

Answer:

Refers to above attachment.......

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