Question

$\Large{\underline{\boxed{\bf\star Question }}}$

See the attachment, here's two circuits. Second circuit is simplified of the first. Is there any mistake in the simplification of my circuit? If there is mistake, tell the mistake. Give reason also for your answer. How to solve these types of circuits? Also correct this circuit if it is wrong.

Answer all these questions.. please..!

Class-10 Electricity

Answer 1

Answer:

1st circuit diagram has a correction, mentioned in my attachment,,,

&

I think 2nd circuit diagram is correct, their must be no correction,,,

Explanation:

hope it's helpful,,

@—

$\huge \: op \: boy$

Answer 2

★ Solution :-

Yes, the simplication given in the attachment of the initial circuit is correct.

Let's now look at why the simplication is correct by understanding the different parts of the circuit.

Before this please try to recall the concept of current in the series and parallel combination. We know that in series combination, the current remains equal between the parts and thus flows evenly in the circuit. In parallel combination, current get's divided between the parts and thus flows in circuit either by taking turns within the connections or dividing. Here current is assumed to flow from A to B.

• First Circuit ::

Here we see that two ending terminals are at A and B. We have four resistances here namely R₁, R₂, R₃ and R₄ which are connected in the circuit. Now we need to find their arrangement. We can see that R₁ and R₃ are in parallel combination with each other since current is getting divided between them. Now we see that the current flows evenly from R₂ to the combination of (R₁ and R₃). This means that R₂ is in series combination with (R₁ and R₃). Then we see that again the current gets divided between the connection of R₂ and R₄. This means that R₄ is in parallel combination with [R₂ which is in series combination with (R₁ and R₃ which are parallelely connected to each other)].

Here brackets show the existing combinations.

• Second Circuit ::

In this circuit we can clearly see the combination. We see that the terminal points are A and B. Here R₁ is in parallel combination with R₃. Now this combination of (R₁ and R₃) is in series combination with R₂. Then we see that this combination of three resistances is in parallel combination with R₄. This means, R₄ is in parallel combination with [R₂ which is in series combination with (R₁ and R₃ which are parallelely connected with each other)].

On comparing both the circuits we get, that the Second Circuit is the correct simplication of the First Circuit.

• Ways to solve such question ::

The simplest way to solve such questions is using the diagram of flow oc current. Current is the best method to describe the arrangements of resistors. The following are the steps for this method :-

>> Firstly draw the circuit in rough and then assume the flow of current from a terminal point to another terminal point of circuit.

>> Start marking the flow of current from the initial terminal point using arrows over the lines of circuit similar to this ----->---- .

>> Wherever you see the circuit parts getting divided in two directions, mark flow of current in both directions.

>> Wherever the circuit parts are going straight, just keep drawing the arrows.

>> After you are done with marking arrows till the another terminal point, just see the position of arrows

>> Divergent arrows will show the parallel combination and straight arrows will show the series combination. Make the equivalent groupings and the circuit will be formed.

Refer the attachment to understand this method more precisely.