Question

$\large\underline\mathfrak\red{Question \: :- }$
While landing at airport, a pilot made an angle of depression of 20°. Average speed of the plane was 200 km/hr. The plane reached the ground after 54seconds. Find the height at which the plane was when it started landing. ( sin 20° = 0.342 )
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Answer 1

Step-by-step explanation:

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Answer 2

ANSWER = 1026 m

Let the height

Of plane = h

Average speed = 200 km/ hr

= 200 × 5 / 18

= 500 / 9 m/ s

Time taken = 54 s

Distance = speed × time

Distance = 500 / 9 × 54

= 3000 m

Consider Right Triangle ABC ,

AC = 3000 m

AB = h

< ACB = 20 °

Sin 20 = AB / AC

h = AC × sin 20

= 3000 × 0.342

= 1026 m