Question

$\large{\underline{\rm{\pink{Question:-}}}}$
☛These are isotopes.
☛Find:- • Electrons
• Protons
• Neutrons

Hints:-
Isotopes:- ❥Same atomic number
❥ Different mass number​

Answer 1

$\mathtt{\huge{\underline{\red{Solution:-}}}}$

$\mathtt{\large{\underline{\green{Answer\:1:-}}}}$

✏ 1H¹ , 1H² ,1H³

• e- = 1 1 1

• p+ = 1 1 1

• n = 0 1 2

e = p = atomic number of atoms = 1 , 1, 1

1H¹

=> 1 = 1 + n

=> n = 1 - 1

=> n = 0

1H²

=> 2 = 1 + n

=> n = 2 - 1

=> n = 1

1H³

=> 3 = 1 + n

=> n = 3 - 1

=> n = 2

$\mathtt{\large{\underline{\green{Answer\:2:-}}}}$

✏ 17Cl^35, 17 Cl^37

• e- = 17 , 17

• p+ = 17 , 17

• n = 18 , 20

e = p = atomic number of atoms = 17 , 17

17 Cl ^35

=> 35 = 17 + n

=> 35 - 17 = n

=> n = 18

17 Cl^37

=> 37 = 17 + n

=> 37 - 17 = n

=> n = 20

$\mathtt{\large{\underline{\green{Answer\:3:-}}}}$

6C¹² , 6C¹³ , 6C^14

• e- = 6 , 6, 6

• p+ = 6 , 6, 6

• n = 6 , 7 , 8

e = p = atomic number of atoms = 6 , 6, 6

6C^12

=> 12 = 6 + n

=> n = 12 - 6

=> n = 6

6C¹³

=> 13 = 6 + n

=> n = 13 - 6

=> n = 7

6C^14

=> 14 = 6 + n

=> n = 14 - 6

=> n = 8

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Answer 2

Solution:

✏ 1H¹ , 1H² ,1H³

e- = 1 1 1

p+ = 1 1 1

n = 0 1 2

e = p = atomic number of atoms = 1 , 1, 1

1H¹

=> 1 = 1 + n

=> n = 1 - 1

=> n = 0

1H²

=> 2 = 1 + n

=> n = 2 - 1

=> n = 1

1H³

=> 3 = 1 + n

=> n = 3 - 1

=> n = 2

Answer2:−

✏ 17Cl^35, 17 Cl^37

e- = 17 , 17

p+ = 17 , 17

n = 18 , 20

e = p = atomic number of atoms = 17 , 17

17 Cl ^35

=> 35 = 17 + n

=> 35 - 17 = n

=> n = 18

17 Cl^37

=> 37 = 17 + n

=> 37 - 17 = n

=> n=20

Answer3:−

6C¹² , 6C¹³ , 6C^14

e- = 6 , 6, 6

p+ = 6 , 6, 6

n = 6 , 7 , 8

e = p = atomic number of atoms = 6 , 6, 6

6C^12

=> 12 = 6 + n

=> n = 12 - 6

=> n = 6

6C¹³

=> 13 = 6 + n

=> n = 13 - 6

=> n = 7

6C^14

=> 14 = 6 + n

=> n = 14 - 6

=> n = 8