Question

$\Large{\underline{\underline{\bf{Question:-}}}}$
If $\frac{5x}{3} - 4 = \frac{2x}{5}$ , then the numerical value of (2x - 7) is -​

Answer 1

$\large \bf \purple { \: ☣ \: Given\: \: ☣}$

$\sf \cfrac{5x}{3} - 4 = \cfrac{2x}{5}$

$\large \bf \purple { \: ☣ \: To \: find \:☣ \: }$

$\sf We \: have \: to \: find \: the \: value \: of \: (2x-7).$

$\large \bf \purple { \: ☣ \: Solution \:☣ \: }$

$\green➠ \sf \cfrac{5x}{3} - 4 = \cfrac{2x}{5}$

$\green➠ \sf \cfrac{5x}{3} - \cfrac{2x}{5} = 4$

$\green ➠\sf \cfrac{25x -6x }{15} = 4$

$\green ➠\sf \cfrac{19x}{15} =4$

$\green➠\sf19x=4(15)$

$\green ➠\sf x= \cfrac{60}{19}$

$\sf Substituting \: x= \cfrac{60}{19} \: in \: (2x-7):-$

$\green ➠\sf 2x-7$

$\green ➠\sf 2( \dfrac{60}{19} )-7$

$\green ➠\sf \cfrac{120}{19} - 7$

$\green ➠\sf \cfrac{120-133}{19}$

$\green ➠\sf \cfrac{ - 13}{19}$

$\sf \blue {\therefore (2x-7)= \cfrac{ - 13}{19} \: \: when \: \cfrac{5x}{3} - 4 = \cfrac{2x}{5} . }$

_____________________

All done :)

Answer 2

Given Question :-

$\sf \: If \: \dfrac{5x}{3} - 4 = \dfrac{2x}{5} then \: numerical \: value \: of \: (2x - 7) \: is$

Answer

Given -

$\bull \: \: \: \: \sf \: \dfrac{5x}{3} - 4 = \dfrac{2x}{5}$

To Find -

$\bull \: \: \: \: \sf \: numeric \: value \: of \: (2x - 7)$

CALCULATION -

$\rm :\implies\:\dfrac{5x}{3} - 4 = \dfrac{2x}{5}$

$\rm :\implies\:\dfrac{5x - 12}{3} = \dfrac{2x}{5}$

$\rm :\implies\:25x - 60 = 6x$

$\rm :\implies\:25x - 6x = 60$

$\rm :\implies\:19x = 60$

$\rm :\implies\:x = \dfrac{60}{19}$

Now,

Consider,

$\rm :\implies\:2x - 7$

$\rm :\implies\:2 \times \dfrac{60}{19} - 7$

$\rm :\implies\:\dfrac{120}{19} - 7$

$\rm :\implies\:\dfrac{120 - 133}{19}$

$\rm :\implies\:\dfrac{ - 13}{19}$

So,

$\rm :\implies\:numerical \: value \: of \: 2x - 7 = \dfrac{13}{19}$