Question

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The drain cleaner, Drainex contains small bits of aluminum which react with caustic soda to produce dihydrogen. What volume of dihydrogen at 20 °C and one bar will be released when 0.15g of aluminum reacts?

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$⟶ \bf\purple{Latex \: answer \: be \: \: used.}$

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Answer 1

Answer:

By the above equation we can say that,

2 moles of aluminum releases 3 moles of hydrogen gas.

We can find the moles of aluminum produced by,

number of moles = Molar Given massmass 0.15g27 =

5.56X10-3 moles

Thus moles of hydrogen can be founded by,

= 3 x moles of aluminium

= 3 x 5.56 x 10-3

= 8.33 x 10-3 moles

Answer 2

$❒\large{\underline{\underline{\red{\color{red}{\pmb{\sf{ Question :- }}}}}}}$

The drain cleaner, Drainex contains small bits of aluminum which react with caustic soda to produce dihydrogen. What volume of dihydrogen at 20 °C and one bar will be released when 0.15g of aluminum reacts?

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$❒\large{\underline{\underline{\red{\color{red}{\pmb{\sf{ Answer :- }}}}}}}$

Al react with caustic soda to produce dihydrogen. reaction will be

2Al + 2NaOH + 2H2O -->2NaAlO2 + 3H2

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⚘here we see that, 2 mol of Al produce 3 mole of H2

∴ 2 × 27 g of Al produce 3 × 2 g of H2 .

∴ 54 g of Al produce 6g of H2.

∴ 1 g of Al produce 6/54 = 1/9 g of H2.

∴ 0.15g of Al produce 0.15/9 g of H2

so,

number of mole of H2 produce = weight of HE produce/molar weight of H2

= (0.15/9)/2

= 0.15/18 = 0.00833 mol

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now,

${\boxed{\bf\purple{use \: formula, \: PV = nRT }}}$

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Here,

⚘ P = 1 bar or 0.987 atm

⚘T = 20°C or 293K

⚘n = 0.00833 mol

⚘R = 0.0821 atm dm³/K/mol

⚘V = ?

V = 0.00833 × 0.0821 × 293/0.987

= 0.203 dm³

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we know,

${\boxed{\bf\pink{1 dm³ = 1000 mL}}}$

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so, Volume of H2 = 1000 × 0.203mL

${\boxed{\bf\green{➼ 203 \: mL.}}}$

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