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$\Large{\underline{\underline{\textsf{Answer the Questions in Attachment.}}}}$

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Answer 1

Answer:

10.

We have to reduce fraction  $\large \dfrac{10080}{40320}$

First divide the fraction by 10 we get

$\large \dfrac{1008}{4032}$

Now 4032 is completely divisible by 1008

4 times 1008 is equal to 4032

So we get  $\large \dfrac{1 }{4}$

9.

Let from x should subtract to get 5 / 4

$\large x-\dfrac{-5}{6}=\dfrac{5}{4}\\\\\\\large x=\dfrac{5}{4}+\dfrac{-5}{6}\\\\\\\large x= \dfrac{15-10}{12}\\\\\\\large x=\dfrac{5}{12}$

8.

Let y should add to get 3 / 4

$\large y+\dfrac{-2}{7}=\dfrac{3}{4}\\\\\\\large y=\dfrac{2}{7}+\dfrac{3}{4}\\\\\\\large y=\dfrac{8+21}{28}\\\\\\\large y=\dfrac{29}{28}$

7.

We have to divide the fraction

$\large \dfrac{-2}{12}/\dfrac{3}{4}\\\\\\\large \dfrac{-2}{12}\times\dfrac{4}{3}\\\\\\\large \dfrac{-2}{3}\times\dfrac{1}{3}\\\\\\\large \dfrac{-2}{9}$

6.

First make the denominator same

Multiply by 4 and 5 in both fraction

$\large \dfrac{-2}{5}\times\dfrac{4}{4}\\\\\\\large \dfrac{-8}{20}\\\\\\\large \text{Now in second fraction}\\\\\\\large \dfrac{3}{4} \times\dfrac{5}{5} \\\\\\\large \dfrac{15}{20}\\\\\\\large \text{So rational number between \dfrac{-8}{20} \ and \ \dfrac{15}{20} }\\\\\\\large \dfrac{-7}{20}, \ \dfrac{-6}{20}, \ \dfrac{-5}{20} \ ....$

5.

Mod mean value will be positive only

$[\large \dfrac{-2}{12}+\dfrac{-3}{4}]\\\\\\\\\large \dfrac{-2-9}{12}\\\\\\\large \dfrac{-11}{12} \\\\\\\large \text{Becasue of mod value will be positive so answer \dfrac{11}{12} }$

4.

We have to simplify

$\large \dfrac{-7}{6}+ \dfrac{3}{8} -\dfrac{5}{4}\\\\\\\large \dfrac{-7\times4+3\times3-5\times6}{24}\\\\\\\large \dfrac{-28+9-30}{24}\\\\\\\large \dfrac{-51}{24}\\\\\\\large \dfrac{-17}{8}$

3.

Additive inverse of 2 / 3 = - 2 / 3

Multiplicative inverse of 3 / 5 = 5 / 3

Now their multiplication

$\large \dfrac{-2}{3} \times\dfrac{5}{3} \\\\\\\large \dfrac{-10}{9}$

2.

$\large 5+\dfrac{1}{4}-(-\dfrac{3}{8} )\\\\\\\large \dfrac{20+1}{4}+\dfrac{3}{8}\\\\\\\large \dfrac{21}{4}+\dfrac{3}{8}\\\\\\\large \dfrac{42+3}{8}\\\\\\\large \dfrac{45}{8}$

1.

We have to represent following on number line :

$\large \dfrac{2}{3}, \ \dfrac{5}{2}, \ and \ \dfrac{-4}{5}$

Refers to plot on coordinate plane.

Answer 2

Answer:

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