Question

$\Large{\underline{\underline{\tt{\purple{Hello !!}}}}}$

Find the difference between 100th and 50th term of an AP whose common difference is -2.


⚠️ I don't want Unnecessary anwer​

Answer 1

=a+99d-a-49d

=50d

=50×-2

= -100.

HOPE IT WILL HELP YOU.

THANKS.

Answer 2

$\huge\mathfrak\green{☟ \: \: \: answer \: \: \: \: \: ✎}$

$Here$

$T\frac{}{100} = a + (100 - 1) d \\ = a + 99d$

$T \frac{}{50} = a + (50 - 1)d \\ = a + 49d$

$T\frac{}{150} = a + (150 - 1)d \\ = a + 149d$

According to the given Condition,

$100 \times T \frac{}{100} = 50 \times T\frac{}{50}$

$⇒100(a + 99d) = 50( a + 49d)$

$⇒2(a + 99d) = (a + 49d)$

$⇒a + 149d = 0$

$⇒T \frac{}{150} = 0$

And Right option is D

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$\\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$