Psychology, asked by name6082, 4 months ago

Ф≈∴↑↑∑¬↓↑ωФ⇒\\ \leq \alpha \frac{x}{y} \neq \pi \pi \pi \neq \sqrt{x} \neq \geq \sqrt{x} \geq \pi \alpha \beta \beta x_{123} \beta \alpha \frac{x}{y} \alpha \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \lim_{n \to \infty} a_n \sqrt{x}

Answers

Answered by 7potatohead
1

tex]\\ \leq \alpha \frac{x}{y} \neq \pi \pi \pi \neq \sqrt{x} \neq \geq \sqrt{x} \geq \pi \alpha \beta \beta x_{123} \beta \alpha \frac{x}{y} \alpha \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \lim_{n \to \infty} a_n \sqrt{x}[/tex]

Answered by LakshyaMishra15
0
Its not good handwriting
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