Question

$lim \frac{h}{sin \: h} \: = \\ h - > 0$
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Answer 1

We will show that limh→0 sinh h. = 1 and limh→0. 1 − cosh h. = 0, from which it will follow that f (x) = ( sinx) · 0 + (cosx) · 1 = cosx. We thus have the formula