Question

$\lim_{n \to \infty} a_n \alpha \frac{x}{y} \sqrt[n]{x} \sqrt{x} x^{2}$

Answer 1

Answer:

$\frac{x}{y} \sqrt[n]{x} \lim_{n \to \infty} a_n$

Explanation:

Answer 2

Answer:

$\frac{x}{y} \sqrt[n]{x} \pi \lim_{n \to \infty} a_n$

Explanation: