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lim(n tends to infinity)n/n+1
now take n common
=n(1/n+1/n)
but n tends to infinity
so 1/n tends to 0
hence
=n(0+0)
=n*0
=0
Hope it helps....
:)
now take n common
=n(1/n+1/n)
but n tends to infinity
so 1/n tends to 0
hence
=n(0+0)
=n*0
=0
Hope it helps....
:)
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