Question

$log_{10}3=a; log_{10}2=b$ find the value of $log_{5}6$

Answer 1

Step-by-step explanation:

Solution

log_(0.72)(9.6)= log_(72/100)(96/10) =((log_(10) 96-log_(10) 10))/((log_(10) 72 - log_(10)100))

<br>

=(log_(10)(2^(5)xx3)-1)/(log_(10)(2^(3)xx3^(2))-2)

<br>

=(5a+b-1)/(3a+2b-2)