Math, asked by addhyangarg18, 9 months ago


 log_{2}(x)  +  log_{8}(x) +  log_{32}(x)   =  \frac{23}{15}
find the value of x

Step by step explanation pls​

Answers

Answered by rubiasthana
0

Answer:

log 2x + log 8x = log 10x

32x = fraction

Step-by-step explanation:

23 find the value of x

32x -23x = 9

x =9

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