Question

$log(9) ^{x} = 2 \\ find \: the \: values \: of \: x$
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Answer 1

$log {9}^{x} = 2 \\ \\ = > log( {3}^{2x} ) = 2 \\ \\ = > 2x log(3) = 2 \\ \\ = > 2x \times 0.47712 = 2 \\ \\ = > x \times 0.47712 = 1 \\ \\ = > x = \frac{1}{0.47712} \\ \\ x = 2.0959$

HOPE WILL BE HELPFUL

Answer 2

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