Question

$log( \frac{26}{51} ) - log( \frac{91}{119} )$
log2 = 0.3010 and log 3 = 0.4771​

Answer 1

We know that,

$loga - logb = log \frac{a}{b}$

Therefore,

$log \frac{26}{51} - log \frac{91}{119} \\ = log \frac{ \frac{26}{51} }{ \frac{91}{119} } \\ = log \frac{26 \times 119}{51 \times 91} \\ = log \frac{2}{3} \\ = log2 - log3 \\ = 0.3010 - 0.4771 = - 0.1761$

Answer 2

Answer:

$log{/pink}{Vandana}$