Question

$log( \sqrt{x + y } ) = sec {y}^{2}$
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Answer 1

Answer:

x = (100^sec(y²)) - y

Step-by-step explanation:

log √(x+y) = sec (y²)

log ₐ b = n      then b = aⁿ

log ₁₀ √(x+y) = sec (y²)

√(x+y)  = 10^sec(y²)        /( )²

(√(x+y))² = (10^sec(y²))²

x + y = 100^sec(y²)

x = (100^sec(y²)) - y