Question

$log( x ^{2} + 1) = log(2x)$
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Answer 1

Answer:

$\green {Value \: of \: x=1 \: Or \: x = 1 }$

Step-by-step explanation:

$\red {log(x^{2}+1) = log(2x)}$

$\implies x^{2}+1 = 2x$

$\implies x^{2}- 2x + 1 =0$

$\implies x^{2} - 2\times x \times 1 + 1^{2} = 0$

$\implies (x-1)^{2} = 0$

$\implies (x-1) = 0 \: Or \: x-1 = 0$

$\implies \green {x=1 \: Or \: x = 1 }$

Therefore.,

$\green {Value \: of \: x=1 \: Or \: x = 1 }$

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Answer 2

Answer:

Step-by-step explanation: