Question

$logx( \frac{1}{16 ?}) = - 2 ,then \: x=?$
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Answer 1

Answer:

$\huge\bold\red{ANSWER}$

Step-by-step explanation:

$\large{\underline{\rm{\red{SOLUTION :}}}}$

$\implies \sf \blue {log_x(\frac{1}{16})=-2}\\ \implies \sf \blue {x^-2=\frac{1}{16}}\\ \implies \sf \blue {\frac{1}{x}=\frac{1}{16}}\\ \implies \sf \blue {x=4,-4}\\ \implies \sf \blue {-2\:is\:not\:possible\:so\:2\:is\:possible}$