Math, asked by sk0922870, 19 hours ago


 < 4x2 - 7y + 8x >  -  \leqslant x2 -  < x2 + y >  - 2y + 8x \geqslant
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Answers

Answered by vijayarajv639
0

Answer:

4x

2

+8xy−2y

2

and 8xy−5y

2

+x

2

it can be written as

4x

2

+8xy−2y

2

+8xy−5y

2

+x

2

By further calculation

= 4x

2

+x

2

+8xy−2y

2

−5y

2

So we get

5x

2

+16xy−7y

2

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