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a solution of NaOH is prepared by dissolving some amount of NaOH in 100 ml of water. If the mole fraction of NaOH is 0.0046, find the amount of NaOH.
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1 gm mole of water or 18 gm of water occupy 22.4 litres
Hence 100 ml water contain -----
=(18gm ×100ml)/22.4 ×1000litres
= 0.08 gm
Let the mass be x of NaOH
NaOH(A)
water(B)
mole fraction of NaOH=nA/ nA+nB
nA =x /40
nB =0.08/18
Further solving
mass of NaOH =0.00073gm
Hence 100 ml water contain -----
=(18gm ×100ml)/22.4 ×1000litres
= 0.08 gm
Let the mass be x of NaOH
NaOH(A)
water(B)
mole fraction of NaOH=nA/ nA+nB
nA =x /40
nB =0.08/18
Further solving
mass of NaOH =0.00073gm
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