Question

$<b>Heya mate..!</b>$
From a copper plate,which is a square of side 12.5 cm,a circular disc of a diameter 7 is cut off.Find the weight of remaing part,if 1sq cm of the plate weighs 0.8g(Assume pie=22/7)

Answer 1

Answer:

Weight of the remaining part is 94.2 g.

Step-by-step explanation:

Given,

   Side of the copper plate = 12.5 cm

∴ Area of the copper plate = side^2

                                  ⇒ ( 12.5 cm )^2

                                  ⇒ 156.25 cm^2

Diameter of the circular disc = 7 cm

∴ Radius of the circular disc = 7 / 2 cm

∴ Area of circular disc = πr^2

                ⇒ ( 22 / 7 x 7 x 7 / 4 cm^2 )

                ⇒ 11 x 3.5 cm^2

                ⇒ 38.5 cm^2

Remaining area = area of square - area of disc

                ⇒ 156.25 cm^2 - 38.5 cm^2

                ⇒ 117.75 cm^2

Weight of 1 cm^2 of plate 0.8 g

As plate & remaining part is of same material. Weight of 1 sq cm of plate = Weight of 1 sq cm of remaining part.

∴ Weight of 1 cm^2 of remaining part = 0.8 g

Weight of 117.75 cm^2 ( remaining part ) = 117.75 x 0.8 g

Weight of the remaining part = 94.2 g

Answer 2

hey mate
refer to attachment