Physics, asked by Anonymous, 9 months ago

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A glass container is sealed with gas at 0.800 atm pressure and 25°C. The glass container can sustain pressure of 2 atm. Calculate the temprature to which gas cab be heated before bursting the container?

Answers

Answered by Anonymous

Solution :

Given :-

▪ Initial pressure of gas = 0.8atm

▪ Initial temperature of gas = 25°C

▪ Max. pressure can be sustained by glass container = 2atm

To Find :-

▪ Temperature of gas at pressure of magnitude 2atm

Concept :-

This question is completely based on concept of 'Gay Lussac's law'.

As per Gay Lussac's law, At constant volume, pressure of a fixed amount of gas varies directly with the temperature.

Mathematically,

$\bigstar\bf\pink{P\propto T}$

Calculation :

$\implies\bf\:\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\\ \\ \implies\sf\:\dfrac{0.8}{298}=\dfrac{2}{T_2}\\ \\ \implies\sf\:T_2=\dfrac{2\times 298}{0.8}\\ \\ \implies\underline{\boxed{\bf{\purple{T_2=745\:K=472\degree{C}}}}}$

Note: K = °C + 273

Answered by XxpawanxX59

Explanation:

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A glass container is sealed with gas at 0.800 atm pressure and 25°C. The glass container can sustain pressure of 2 atm. Calculate the temprature to which gas cab be heated before bursting the container?​