Find the relationship b/w Electric field and potential difference!!!!!
Answers
To derive :
Relationship between Electric Field and Electric Potential .
Proof:
First of all , let's consider a charge q located at a specified point and emitting electric field . We shall also consider 2 closely located points named as A and B.
The distance between A and B be dx.
Since the dx distance is extremely small, we can consider that the Electric field E (from the charge) remains same at both the points.
Now the work done to move a unit positive charge from A to B will be :
The negative sign denoted that the work done was against the Electric Field Direction.
For a unit positive charge , we know that work done us equal to the potential difference dV.
So we can say that Electric Field is the gradient of Electric Potential with respect to distance.
Answer:
The relationship between potential and field (E) is a differential: electric field is the gradient of potential (V) in the x direction. This can be represented as: Ex=−dVdx E x = − dV dx . Thus, as the test charge is moved in the x direction, the rate of the its change in potential is the value of the electric field.
Explanation:
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