Answers Me.... please...
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Step-by-step explanation:
S₁ = 3x² + 3y² + x + 2y - 1 = 0
=> S₁ = x² + y² + x/3 + 2y/3 - 1/3 = 0
S₂ = 2x² + 2y² + 2x - y - 1 = 0
=> S₂ = x² + y² + x -y/2 -1/2
The equation of Radical axis of two circles is given as S₁ - S₂ = 0
=> x² + y² + x/3 + 2y/3 - 1/3 - [x² + y² + x -y/2 -1/2] = 0
=> x² + y² + x/3 + 2y/3 - 1/3 - x² - y² - x + y/2 + 1/2 = 0
=> x/3 - x + 2y/3 + y/2 - 1/3 + 1/2 = 0
=> -2x/3 + 7y/6 + 1/6 = 0
=> 1/6[-4x + 7y + 1] = 0
=> -4x + 7y + 1 = 0
=> 4x - 7y - 1 = 0
=> 4x - 7y = 1.
Hence "A" is the answer.
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