Question

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$the \: motion \: of \: a \: particle \: of \: mass \: x \: is \: described \: by \: y = ut + \frac{1}{2} {gt}^{2} . \: find \: the \: force \: acting \: on \: the \: particle \:$
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Answer 1

Answer:

v=ut+

2

1

×gt

2

Differentiate y with respect to t which gives velocity as dy/dt = v

dt

dv

= u+

2

1

g(2t)

v=u + gt -------------------Eqn (1)

Differentiate v with respect to t which gives velocity as d2y/dt2 = dv/dt = a

dt

dv

= 0 + g

a = g ----------------------Eqn (2)We know that force acting on a mass m is given by F = ma

Now from Eqn (2), substitute a =g, Hence, F = mg