Question

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$\huge \: hlo \: guys \\ \\ \huge \: gm \\ \\ \small \bf{find \: the \: value \: of \: sin \: 15}$
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Answer 1

Sin15°

=sin(45°-30°)

=sin 45°.cos 30°-cos45°.sin 30°

=1/ √2. √3/2-1/ √2.1/2

= √3/ 2√2 - 1/2 √2

= √3-1/ 2 √2

Answer 2

We know that sin(A - B) = sin A cos B - cos A sin B sin 15° = sin(45° - 30°) = sin 45° cos 30°- cos 45° sin 30° sin 15° = (1/√2) (√3/2) - (1/√2) (1/2) sin 15° =(√3 - 1)/2√2