Question

$<h1>content-quality$

$<b>$One end of a copper rod of length 1.0 m and area of cross-section 103 m2 is immersed in boiling water and the other end in ice. If the coefficient of thermal conductivity of copper is 92 cal/m-sc and the latent heat of ice is 8 104 cal kg, then the amount of ice which will melt in one minute is

Answer 1

Hey Friend✌
here is ur Ans ⬇️⬇️⬇️


✅Length of Copper rod, DC = 1m

Area of cross Sectional area, A = 10^-3 m^2

Coefficient of thermal conductivity of copper
K = 92 /cal/m/s

Lanted heat of ice , L = 8 x 10^4 cal/kg

Here, One end of a copper rod of length 1.0 m and aea of cross cross section 10^3 m^3 is immersed in boiling water and the other end in ice.

Heat generated per minute, H = kAdT / dx x t

= 92 x 10^-3 x (100 - 0) / 1 x 60 cal

= 92 x 10 x 60 cal

= 55200 cal


Heat required to melt the ice of mass mL

m x 8 x 104 = 55200

m = 55200 / 8 x 10^4

= 0.69 kg


✅Hope This Helps u ☺

Answer 2

length of copper rod , dx = 1m

area of cross sectional area , A = 10^-3 m²

coefficient of thermal conductivity of copper , k = 92 cal/m/s

latent heat of ice, L = 8 × 10⁴ cal/Kg

here, One end of a copper rod of length 1.0 m and area of cross-section 10³ m³ is immersed in boiling water and the other end in ice.

heat generated per minute , H = kAdT/dx × t

= 92 × 10^-³ × (100 - 0)/1 × 60 cal

= 92 × 10 × 60 cal

= 55200 cal

heat required to melt the ice of mass m = mL
m × 8 × 104 = 55200

m = 55200/8 × 10⁴ = 0.69kg