Question

$<marquee direction= "right"> Please solve this.$​

Answer 1

$\tan(5) \times \tan(25) \times \tan(30) \times \tan(65) \times \tan(85) = \frac{1}{ \sqrt{3} } \\ \tan(5) \times \tan(85) \times \tan(25) \times \tan(65) \times \tan(30) = \frac{1}{ \sqrt{3} } \\ \tan(5) \times \tan(90 - 5) \times \tan(25) \times \tan(90 - 25) \times \tan(30) = \frac{1}{ \sqrt{3} } \\ \tan(5) \times \cot(5) \times \tan(25) \times \cot(25) \times \tan(30) = \frac{1}{ \sqrt{3} } \\ \tan(5) \times \frac{1}{ \tan(5) } \times \tan(25) \times \frac{1}{ \tan(25) } \times \tan(30) = \frac{1}{ \sqrt{3} } \\ \tan(30) = \frac{1}{ \sqrt{3} }$

Answer 2

Step-by-step explanation:

tan(5)×tan(25)×tan(30)×tan(65)×tan(85)=

3

1

tan(5)×tan(85)×tan(25)×tan(65)×tan(30)=

3

1

tan(5)×tan(90−5)×tan(25)×tan(90−25)×tan(30)=

3

1

tan(5)×cot(5)×tan(25)×cot(25)×tan(30)=

3

1

tan(5)×

tan(5)

1

×tan(25)×

tan(25)

1

×tan(30)=

3

1

tan(30)=

3

1

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