Question

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a vessel of 120 ml capacity contain a certain amount of gas at 35 degree Celsius and 1.2 bar pressure the gas is transferred to another vessel of volume 180 ml at 35 degree celsius what would be its pressure​

Answer 1

Here , P1=1.2 bar, V1=120 ml , P2=?, V2=180 ml

temp of gas is at 35°c

e.g. temp is constant

we have apply Boyle's law

P1V1 = P2V2

Now,

1.2 × 120 = P2 × 180

=> 144 = P2 × 180

=> P2 × 180 = 144

=> P2 = 144/180 = 0.8

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Answer 2

Given

initial

v1 = 120ml

t1 = 35°c

p1 = 1.2bar

final

v2 = 180ml

t2 = 35°c

p2= ?

using combined gas equation

p1*v1/t1=p2*v2/t2

p2 = p1*v1*t2/t1*v2

on putting the value

p2 = 1.2*120*35/35*180

p2 = 12*120/1800=4/5= 0.8bar

so final pressure of vessel is 0.8bar