Question

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if the magnitude of two vectors are 3 and 4 and their scalar product is 6 then find the angle between the two vectors​

Answer 1

Here. |A|=3, |B|=4, A.B=6

therefore. cos theta = A.B/|A||B|

=6/3×4

=1/2

Hence theta = 60°

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Answer 2

Answer:

We have,

Scalar Product = I a I I b I . CosФ

Here Ф refers to the angle between the vectors.

=> A . B = I a I I b I . CosФ

A . B = 6 ; I a I I b I = 3 * 4

Substituting in the formula we get,

6 = 3 * 4 . CosФ

6 = 12 . CosФ

=> Cos Ф = 6 / 12 = 1 / 2

We know that Cos 60° is 1 / 2 . Hence the angle between them would be 60°

Hence Ф = 60°.