Question

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what will be the minimum pressure required to compress 500 DM cube of air at 1 bar to 200 DM cube at 30 degree Celsius ​

Answer 1

Volume of gas(V1) = 500dm3   (given)

Pressure of gas (p1) = 1 bar    (given)

Volume of compressed gas (V2) = 200dm3 

(given)

Now ,let P2 be the pressure required to compress the gas.

Therefore at constant temperature P1 V1 = P2 V2(Boyle’s Law)

As a result P2 = P1 V1 / V2 = 1 X 500/200

= 2.5 bar

Therefore, the minimum pressure required is 2.5 bar.

hope it helps you❤

Answer 2

Given,

P1=1

P2=?

V1=500 dm^3

V2=200dm^3

Apply Boyle's law P1V1 = P2V2 to calculate P2 as temp remains constant.

P2= P1V1'/V2

=1 bar × 500 dm^3 / 200 dm^3

= 2.5 bar

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