Question

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what will be the minimum pressure required to compress 500 DM cube of air at 1 bar to 200 DM cube at 30 degree Celsius​

Answer 1

P1= 1

P2= ?

V1= 500 dm^3

V2= 200dm^3

Applying Boyle's law

P1V1=P2V2 to calculate P2 as temp remains constant.

P2= P1V1/V2

= 1 bar × 500 dm^3/200dm^3

= 2.5 bar

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Answer 2

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$<marquee>Mahir$