Question

$<marquee> Five years ago Bina's age was the square of Seema's age. In fifteen years, Bina's Age would be 1.5 times Seema's age. Find the present ages. (Take Seema’s age five Years ago to be x) <marquee>$​

Answer 1

Step-by-step explanation:

let age of seema be x

let present age of bina is y

=>age of seema before 5 yrs is x-5

5 yrs ago age of seema is (x-5)^2

I.e. y-5

in 15 yrs

age of seema is x+15

age of bina is 1.5(x+15)

i.e.y+15

eq1--(x-5)^2=y-5

eq 2 1.5(x+15)= y+15

hence solve and get answer