Math, asked by Anonymous, 10 months ago

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clear my doubt pls​

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Answered by Anonymous
2

Answer:

Given:-

⇢ At the beginning of a month a factory has enough material to make 240 tonnes of Steels in a month. If 60 more tonnes of steel is to be made that month.

Find:-

⇢ How long will the materials last.

Calculations:-

\sf{240 + 60 = 300 \: tonnes}

This is in inverse proportion:-

  • Let x be the time the material lasts.

  • ★ 240:300 :: 30:x

\sf{300x = 240 \times 30}

\sf{x = \dfrac{7200}{300}}

{\boxed{\sf{x = 24}}}

Therefore, 24 days the material last.

Answered by BrainlyEmpire
3

Answer:

In 30 days steel manufactured =240 tonnes

Now, 60 more tonnes of steel is to be manufactured in that month.

So,

240+60=300 Tonnes of steel to be manufactured in the month.

Therefore,

More steel manufactured, fewer days the material will last.

This is an inverse proportion.

240:300::30:x

300x=240.30

300x=7200

x= 7200/300

x=24 days

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