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pKa = log(10)[CH3COOH] - 2*log(10)[H +]. For acetic acid pKa = 4.76 and -log( 10)[H+] = pH ... The required pH of 0.1 M solution of acetic acid is 2.88.......
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Cute111:
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the required ph of 0.1m of solution of acetic acid is 2.88
mark it as brainlist plz
mark it as brainlist plz
me thnx yr
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