Question

$<marquee>$☺☺°°°°°°°TELL ME THE ANSWER WITH COMPLETE SOLUTION°°°°°°°°☺☺

Answer 1

pKa = log(10)[CH3COOH] - 2*log(10)[H +]. For acetic acid pKa = 4.76 and -log( 10)[H+] = pH ... The required pH of 0.1 M solution of acetic acid is 2.88.......
Hope Ye aapki kuch ittu si help krega...☺☺

Answer 2

the required ph of 0.1m of solution of acetic acid is 2.88

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