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the slope of the graph is constant so object has a constant velocity
work done=change in kinetic energy (work energy theorem)
W=1/2m(v^2-u^2)
as velocity is constant and not changing ,v=u
so,v^2-u^2=0
hence W=0
work done=0
work done=change in kinetic energy (work energy theorem)
W=1/2m(v^2-u^2)
as velocity is constant and not changing ,v=u
so,v^2-u^2=0
hence W=0
work done=0
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