Question

$<marquee>$please answer this one

Answer 1

x^2+(1-2i)x-2i=0
x^2+x-2ix-2i=0
x(x+1)-2i(x+1)=0
(x+1)(x-2i)=0
x+1=0 x=-1....(i)
x-2i=0 x=2i....(ii)
So, the value of x=-1,2i