Math, asked by Anonymous, 8 months ago

$<p style="color:cyan;font-family:cursive;background:black;font size:25px;"> Q. A man is 4 times as old as his son . After 16 years ge will be only twice as old as his son. Find their present ages...$ . $<body aquacolor=b>$ <br /> $\large\orange{}$ <br /> $<font color=red>$ <br /> $<marquee>PLEASE SOLVE </marquee>$

Answers

Answered by aayushprat7

2

Answer:

At present :

At present :Son age = 8 years

At present :Son age = 8 yearsFather age = 32 years

Step-by-step explanation:

At present:

Age of son = x years

His Father age = 4x years

After 16 years:

Age of son = (x+16) years

Father age = (4x+16) years

According to the problem given,

Therefore,

At present :

Son age = x = 8 years

Father age = 4x=4×8 = 32 years

•••♪

Answered by dimprajapati

4

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