Math, asked by Anonymous, 9 months ago

&lt;p style="color:red..orange ;font-family:cursive;background: yellow;font size:25px;"&gt; Q. Find two no. such that one of them is five times the other and their difference is 132.. &lt;body aquacolor=b&gt; <br />\large\orange{} <br />&lt;font color=red&gt; <br />&lt;marquee&gt;PLEASE SOLVE  &lt;/marquee&gt;

Answers

Answered by pinjaraarifisha
4

Answer:

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&lt;p style="color:cyan;font-family:cursive;background:black;font size:25px;"&gt; answer is below ✌️✌️

Let x and y are two numbers

one of the them is five times the other

x=5y......................(1)

Their difference is 132

x-y=132 ..................(2)

Put the value of x in above equation

5y-y=132

4y=132

4y/4=132/4 (Divide by 4 both sides)

y=33

Put the value of y in equation (1)

x=5y

x=5(33)

x=165

so x,y = 33, 165

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Answered by Anonymous
1

Answer:

Let x and y be the two numbers such that x=5y

According to the question-

x−y=132

5y−y=132

⇒y= 132/4 =33

Therefore,

x=5y=5×5×33=165

Hence the two numbers are 33 and 165.

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