Math, asked by Anonymous, 10 months ago

&lt;p style="color: red , orange ,  ;font-family:cursive;background:  yellow;font size:25px;"&gt; Q.Mrs. Jain is 27 years older than her daughter Nilu.   After 8 years she will be twice as old as neelu . Find their present ages. .. &lt;body aquacolor=b&gt; <br />\large\orange{} <br />&lt;font color=red&gt; <br />&lt;marquee&gt;PLEASE SOLVE  &lt;/marquee&gt;

Answers

Answered by pinjaraarifisha
3

Answer:

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&lt;p style="color:cyan;font-family:cursive;background:black;font size:25px;"&gt; answer is below ✌️✌️

Mrs. Jain = M

Daughter = D

M = 27 + D

M = 2D + 8

27 + D = 2D + 8

D = 19

M = 46

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Answered by Anonymous
1

let assume -

let the age of nilu be x years

then age of Mrs. Jain will be (x+27)years

after 8 years-

age of nilu will be x+8 years

age of Mrs. Jain will be x+8+27 = x+35 years

given -

Mrs Jain will be twice as old as neelu

solution -

x + 35 = 2(x + 8)

x + 35 = 2x + 16

2x - x = 35 - 16

x = 19

then age of Mrs. Jain will be=

x + 27 = 19 +27 = 46 years

therefore -

age of neelu = 19

age of Mrs. jain= 46

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